An electric dipole of moment is at the origin

PHYSICS · Single correct · CBSE · Physics · Electric Charges and Fields · Electric Charges and Fields

Problem

An electric dipole of moment p⃗=(i^−3j^+2k^)×10−29 C⋅m\vec{p} = (\hat{i} - 3\hat{j} + 2\hat{k}) \times 10^{-29} \text{ C}\cdot\text{m} is at the origin (0,0,0)(0, 0, 0) . The electric field due to this dipole at r⃗=+i^+3j^+5k^\vec{r} = +\hat{i} + 3\hat{j} + 5\hat{k} (note that r⃗⋅p⃗=0\vec{r} \cdot \vec{p} = 0 ) is parallel to: (1) (+i^−3j^−2k^)(+\hat{i} - 3\hat{j} - 2\hat{k}) (2) (−i^+3j^−2k^)(-\hat{i} + 3\hat{j} - 2\hat{k}) (3) (+i^+3j^−2k^)(+\hat{i} + 3\hat{j} - 2\hat{k}) (4) (−i^−3j^+2k^)(-\hat{i} - 3\hat{j} + 2\hat{k})

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