Define p(x)= cases |x-1| ,x-1 , , & x 1, 0, & x=1

MATHEMATICS · Single correct · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Define p(x)={∣x−1∣ x−1 ,x≠1,0,x=1.p(x)= \begin{cases} \dfrac{|x-1|}{\,x-1\,}, & x\ne 1,\\ 0, & x=1. \end{cases} What is the magnitude of the jump discontinuity of pp at x=1x=1? (a) −2-2 (b) 11 (c) 22 (d) 00

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