A neutron-induced fission of uranium is represented as

CHEMISTRY · Multi-part · US High School · Chemistry · Atomic Structure & Nuclear · Atomic Structure & Nuclear

Problem

A neutron-induced fission of uranium is represented as 92235U+01n  →  54140Xe+X+2 01n^{235}_{92}\mathrm{U} + ^{1}_{0}\mathrm{n} \;\rightarrow\; ^{140}_{54}\mathrm{Xe} + X + 2\,^{1}_{0}\mathrm{n} (i) Determine the mass number and atomic number of nucleus XX, and hence write its symbol. (ii) Using the atomic masses given below, calculate the QQ-value of the fission reaction. 92235U:  235.043929 u^{235}_{92}\mathrm{U}:\;235.043929\,\text{u} 54140Xe:  139.921610 u^{140}_{54}\mathrm{Xe}:\;139.921610\,\text{u} 3894Sr:  93.915356 u^{94}_{38}\mathrm{Sr}:\;93.915356\,\text{u} 01n:  1.008665 u^{1}_{0}\mathrm{n}:\;1.008665\,\text{u} (Use 1 u=931.5 MeV1\,\text{u}=931.5\,\text{MeV}.)

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