Find the locus of the foot of perpendicular from the centre upon any normal to the…

MATHEMATICS · Subjective · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

Find the locus of the foot of perpendicular from the centre upon any normal to the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 .

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