CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

If y=sin⁡[cos⁡(sin⁡x)]y = \sin[\cos(\sin x)] , then dy/dx=dy/dx = (a) −cos⁡[cos⁡(sin⁡x)]sin⁡(cos⁡x)⋅cos⁡x-\cos[\cos(\sin x)]\sin(\cos x) \cdot \cos x (b) −cos⁡[cos⁡(sin⁡x)]sin⁡(sin⁡x)⋅cos⁡x-\cos[\cos(\sin x)]\sin(\sin x) \cdot \cos x (c) cos⁡[cos⁡(sin⁡x)]sin⁡(cos⁡x)⋅cos⁡x\cos[\cos(\sin x)]\sin(\cos x) \cdot \cos x (d) cos⁡[cos⁡(sin⁡x)]sin⁡(sin⁡x)⋅cos⁡x\cos[\cos(\sin x)]\sin(\sin x) \cdot \cos x

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