For the ellipse ( x^ 2 49 + y^ 2 25 =1 )

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

For the ellipse x249+y225=1\dfrac{x^{2}}{49}+\dfrac{y^{2}}{25}=1, what is its eccentricity? (a) 57\dfrac{5}{7} (b) 67\dfrac{\sqrt{6}}{7} (c) 267\dfrac{2\sqrt{6}}{7} (d) 245\dfrac{\sqrt{24}}{5}

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