Calculate the approximate altitude (above Earth’s surface) of a geostationary satellite

PHYSICS · Single correct · A Level · Physics · Fields and their consequences · Fields and their consequences

Problem

Calculate the approximate altitude (above Earth’s surface) of a geostationary satellite. Take G=6.67×10−11 N m2kg−2G = 6.67\times10^{-11}\,\text{N m}^2\text{kg}^{-2}, M⊕=5.97×1024 kgM_{\oplus}=5.97\times10^{24}\,\text{kg}, R⊕=6.37×106 mR_{\oplus}=6.37\times10^{6}\,\text{m} and orbital period T=24 hT = 24\,\text{h}. (a) 2.3×107 m2.3\times10^{7}\,\text{m} (b) 4.2×107 m4.2\times10^{7}\,\text{m} (c) 3.6×107 m3.6\times10^{7}\,\text{m} (d) 1.5×107 m1.5\times10^{7}\,\text{m}

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