If the function have the maximum value then

MATHEMATICS · Single correct · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

If the function f(x)=axebx2f(x) = ax e^{bx^2} have the maximum value f(2)=1f(2) = 1 then (a) a=e2a = \frac{\sqrt{e}}{2} and b=−18b = \frac{-1}{8} (b) a=−e2a = \frac{-\sqrt{e}}{2} and b=18b = \frac{1}{8} (c) a=18a = \frac{1}{8} and b=e2b = \frac{\sqrt{e}}{2} (d) a=−e2a = \frac{-\sqrt{e}}{2} and b=−18b = \frac{-1}{8}

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