For , find…

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

For x≠0x\neq 0, find ddx[(x2+1)sin⁡xx]\dfrac{d}{dx}\left[\dfrac{(x^{2}+1)\sin x}{x}\right]. (a) (x2+1)(xcos⁡x−sin⁡x)x2\dfrac{(x^{2}+1)(x\cos x-\sin x)}{x^{2}} (b) x(x2+1)cos⁡x+(x2−1)sin⁡xx2\dfrac{x(x^{2}+1)\cos x+(x^{2}-1)\sin x}{x^{2}} (c) x(x2+1)cos⁡x−(x2−1)sin⁡xx2\dfrac{x(x^{2}+1)\cos x-(x^{2}-1)\sin x}{x^{2}} (d) x(x2+1)cos⁡x+(−x2+2x−1)sin⁡xx2\dfrac{x(x^{2}+1)\cos x+(-x^{2}+2x-1)\sin x}{x^{2}}

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