The orthogonal projection of the point with position vector on the plane is

MATHEMATICS · Single correct · CBSE · Mathematics · Vector Algebra · Vector Algebra

Problem

The orthogonal projection A′A' of the point AA with position vector (1,2,3)(1,2,3) on the plane 3x−y+4z=03x-y+4z=0 is (1) (−1,3,−1)(-1,3,-1) (2) (−12,52,1)\left(-\frac{1}{2},\frac{5}{2},1\right) (3) (12,−52,−1)\left(\frac{1}{2},-\frac{5}{2},-1\right) (4) (6,−7,−5)(6,-7,-5)

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