For an observer standing 40 m from the base of a vertical flagpole

MATHEMATICS · Single correct · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

For an observer standing 40 m from the base of a vertical flagpole, the angle of elevation θ\theta to the top of the pole changes as the pole is raised at a vertical speed of vv meters per second. Which of the following expressions gives dθdt\dfrac{d\theta}{dt} in terms of vv and θ\theta at that instant? (a) v40tan⁡θ\displaystyle \frac{v}{40}\tan\theta (b) v40sec⁡2θ\displaystyle \frac{v}{40}\sec^{2}\theta (c) v40cos⁡2θ\displaystyle \frac{v}{40}\cos^{2}\theta (d) v40cos⁡θ\displaystyle \frac{v}{40}\cos\theta

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