In , it is given that . The altitude from meets at , so that . Use this information…

MATHEMATICS · Multi-part · CBSE · Mathematics · Triangles · Triangles

Problem

In △ABC\triangle ABC, it is given that AB=AC=10 cmAB = AC = 10\text{ cm}. The altitude from AA meets BCBC at DD, so that AD⊥BCAD \perp BC. Use this information to answer the questions below. (a) Prove that △ABD≅△ACD\triangle ABD \cong \triangle ACD. (b) Deduce that DD is the midpoint of BCBC and write the measure of BDBD. If BC=14 cmBC = 14\text{ cm}, give the numerical value of BDBD. (c) Calculate the length of ADAD. Leave the answer in simplest radical form.

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