If has area , with , , and , where , , and are the lengths of the sides opposite…

MATHEMATICS · Single correct · A Level · Mathematics · Trigonometry · Trigonometry

Problem

If △PQR\triangle PQR has area Δ\Delta, with a=2a=2, b=72b=\frac72, and c=52c=\frac52, where aa, bb, and cc are the lengths of the sides opposite angles PP, QQ, and RR, respectively, then 2sin⁡P−sin⁡2P2sin⁡P+sin⁡2P\frac{2\sin P-\sin 2P}{2\sin P+\sin 2P} equals: (1) 34Δ\frac{3}{4\Delta} (2) 454Δ\frac{45}{4\Delta} (3) (34Δ)2\left(\frac{3}{4\Delta}\right)^2 (4) (454Δ)5\left(\frac{45}{4\Delta}\right)^5

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