Let F1(0,−c) and F2(0,c) be two fixed points on the y-axis. A point P(x,y) moves in the plane such that ∣PF2−PF1∣=2a where 2a is a constant. The curve traced by P has its centre at the origin and transverse axis along the y-axis.
(i) Starting from the given condition ∣PF2−PF1∣=2a, derive step by step the Cartesian equation of the curve in the form a2y2−b2x2=1.
(ii) Hence show that the parameters a,b and c satisfy the relation c2=a2+b2.