If 2 and 6 are the roots of the equation

MATHEMATICS · Single correct · CBSE · Mathematics · Polynomials · Polynomials

Problem

If 2 and 6 are the roots of the equation ax2+bx+1=0ax^2 + bx + 1 = 0 , then the quadratic equation, whose roots are 12a+b\frac{1}{2a+b} and 16a+b\frac{1}{6a+b} , is: (A) 2x2+11x+12=02x^2 + 11x + 12 = 0 (B) 4x2+14x+12=04x^2 + 14x + 12 = 0 (C) x2+10x+16=0x^2 + 10x + 16 = 0 (D) x2+8x+12=0x^2 + 8x + 12 = 0

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