In Gauss theorem

PHYSICS · Single correct · ISC · Physics · Electrostatics · Electric field intensity

Problem

In Gauss theorem ∮E⃗⋅dS⃗=qε0\oint \vec{E} \cdot d\vec{S} = \frac{q}{\varepsilon_0}. The surface integral is evaluated by choosing a closed surface, called the Gaussian surface. Here the incorrect statement is (1) (2) (3) (4)

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