Consider the function g(x)= cases x^ 2 -2, & -2 x<1, 3-x, & 1 x 4

MATHEMATICS · Single correct · A Level · Mathematics · Differentiation · Differentiation

Problem

Consider the function g(x)={x2−2,−2≤x<1,3−x,1≤x≤4.g(x)= \begin{cases} x^{2}-2, & -2\le x<1,\\ 3-x, & 1\le x\le 4. \end{cases} Which of the following statements about the existence of absolute extrema of gg on the closed interval [−2,4][-2,4] is true? (a) gg is not differentiable at x=1x=1, so the Extreme Value Theorem cannot be applied on [−2,4][-2,4]. (b) Any absolute extremum of gg must occur at a point where g′(x)=0g'(x)=0, so only interior critical points need to be examined. (c) gg is not continuous on [−2,4][-2,4], so the Extreme Value Theorem does not guarantee absolute extrema. (d) Since gg is discontinuous at x=1x=1, it cannot have an absolute maximum or minimum on [−2,4][-2,4].

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