Let f(x)= cases 3x-2,& 0 x<2

MATHEMATICS · Multi-part · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

Let f(x)={3x−2,0≤x<2,x22+1,2≤x≤6,g(x)=∣x−4∣+1 for 0≤x≤6.f(x)=\begin{cases} 3x-2,& 0\le x<2,\\ \dfrac{x^2}{2}+1,& 2\le x\le6, \end{cases}\qquad \qquad g(x)=|x-4|+1\text{ for }0\le x\le6. Region SS is bounded above by ff, below by gg, and on the left and right by x=0x=0 and x=6x=6, respectively. (1) Part 1: (a) Solve f(x)=g(x)f(x)=g(x) on [0,6][0,6] to determine all xx–coordinates where the graphs of ff and gg intersect. Present exact values. (2) Part 2: (b) Using the intersection points from part (a) and any additional points at which the algebraic form of either ff or gg changes, set up—but do not yet evaluate—the complete sum of definite integrals whose total equals the exact area of region SS. Clearly indicate the limits of integration for each integral. (3) Part 3: (c) Evaluate the integrals you wrote in part (b) to obtain the exact numerical value of the area of SS. Show all work, including antiderivatives and substitution of limits. (4) Part 4: (d) Verify that your answer is non-negative and consistent with the geometric relationship between ff and gg on each subinterval identified in part (b).

Related theory

Browse the problem library