For , determine whether is an antiderivative of by finding and comparing it with…

MATHEMATICS · Subjective · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

For x>0x>0, determine whether K(x)=arctan⁡(x)K(x)=\arctan(\sqrt{x}) is an antiderivative of k(x)=12x (1+x)k(x)=\dfrac{1}{2\sqrt{x}\,(1+x)} by finding K′(x)K'(x) and comparing it with k(x)k(x).

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