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The vertices of a triangle are (0, 0), (1, 0) and (0, 1)
MATHEMATICS · Single correct · CBSE · Mathematics · Coordinate Geometry · Coordinate Geometry
Problem The vertices of a triangle are (0, 0), (1, 0) and (0, 1). Then excentre opposite to (0, 0) is
(1) ( − 1 2 , 1 + 1 2 ) \left(-\frac{1}{\sqrt{2}}, 1 + \frac{1}{\sqrt{2}}\right) ( − 2 1 , 1 + 2 1 )
(2) ( 1 + 1 2 , 1 + 1 2 ) \left(1 + \frac{1}{\sqrt{2}}, 1 + \frac{1}{\sqrt{2}}\right) ( 1 + 2 1 , 1 + 2 1 )
(3) ( 1 + 1 2 , 1 − 1 2 ) \left(1 + \frac{1}{\sqrt{2}}, 1 - \frac{1}{\sqrt{2}}\right) ( 1 + 2 1 , 1 − 2 1 )
(4) ( − 1 2 , 1 − 1 2 ) \left(-\frac{1}{\sqrt{2}}, 1 - \frac{1}{\sqrt{2}}\right) ( − 2 1 , 1 − 2 1 )
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