A straight piece of wire runs horizontally from point X on the left to point Y on the right. A battery is connected across the wire, forming a closed loop. When the battery’s positive terminal is attached to point X and its negative terminal to point Y, conventional current in the wire is from X to Y. If the battery is flipped so that its positive terminal is now at point Y and its negative terminal at point X, which of the following describes the new conventional current in the wire?
(a) It remains from X to Y because electrons now flow in that direction, leaving conventional current unchanged.
(b) The current splits, with equal amounts flowing from X to Y and from Y to X, producing no net current.
(c) It reverses direction and is now from Y to X.
(d) It becomes zero momentarily during the flip and then resumes from X to Y once charges redistribute.