Show that the area of the parallelogram formed by the lines , ,

MATHEMATICS · Subjective · CBSE · Mathematics · Straight Lines · Straight Lines

Problem

Show that the area of the parallelogram formed by the lines 2x−3y+a=02x-3y+a=0, 3x−2y−a=03x-2y-a=0, 2x−3y+3a=02x-3y+3a=0, and 3x−2y−2a=03x-2y-2a=0 is 2a25\frac{2a^2}{5} square units.

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