Doping MgO with Al3+ produces the solid solution Mg1−xAlxO1−x∕2

CHEMISTRY · Single correct · CBSE · Chemistry · d- and f-Block Elements · d- and f-Block Elements

Problem

Doping MgO with Al3+ produces the solid solution Mg1−xAlxO1−x∕2. Which statement best explains why cation vacancies form during this substitution? (a) Because Al3+\mathrm{Al^{3+}} is smaller than Mg2+\mathrm{Mg^{2+}}, extra space appears in the lattice and neighbouring Mg2+\mathrm{Mg^{2+}} ions shift out of their sites, creating vacancies. (b) The higher charge of Al3+\mathrm{Al^{3+}} requires removal of some Mg2+\mathrm{Mg^{2+}} ions so the crystal remains electrically neutral. (c) The substitution increases the lattice energy, pushing some Mg2+\mathrm{Mg^{2+}} ions into interstitial positions and leaving their original sites vacant. (d) To preserve neutrality, the lattice forms O2−\mathrm{O^{2-}} vacancies instead; the resulting distortion is observed as cation vacancies.

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