A rigid diatomic ideal gas undergoes an adiabatic process at room temperature

PHYSICS · Single correct · CBSE · Physics · Thermodynamics · Thermodynamics

Problem

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume for this process is

TV^x = \text{constant}

, then x is: (1)

\frac{3}{5}

(2)

\frac{2}{5}

(3)

\frac{2}{3}

(4)

\frac{5}{3}