In a series RLC circuit driven by an AC source

PHYSICS · Single correct · CBSE · Physics · Alternating Current · Alternating Current

Problem

v(t)=V_m\sin\omega t

, which one of the following gives the correct expression for the peak current amplitude

I_m

? (a)

I_m = \dfrac{V_m}{\sqrt{R^{2}+\left(\omega L+\dfrac{1}{\omega C}\right)^{2}}}

(b)

I_m = \dfrac{V_m}{\sqrt{R^{2}+\left(\omega L-\dfrac{1}{\omega C}\right)^{2}}}

(c)

I_m = \dfrac{V_m}{R+\left|\,\omega L-\dfrac{1}{\omega C}\,\right|}

(d)

I_m = \dfrac{V_m}{\sqrt{R^{2}+\left(\omega L\right)^{2}+\left(\dfrac{1}{\omega C}\right)^{2}}}