Let be given by

MATHEMATICS · Multi-part · CBSE · Mathematics · Relations and Functions · Relations and Functions

Problem

Let f:R→Rf:\mathbb R\to\mathbb R be given by f(x)=∣ax+b∣f(x)=|ax+b|, where a≠0a\ne 0 and bb are real constants. (i) Explain why the range of ff is [0,∞)[0,\infty). (ii) State the condition on aa and bb under which f(x)=0f(x)=0 has a solution, and find that solution. (iii) If the domain of ff is restricted to x≥−bax\ge -\dfrac{b}{a}, determine the new range of ff and justify your result.

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