A region is enclosed by the curve

MATHEMATICS · Subjective · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

A region is enclosed by the curve r=1+cos⁡θr=1+\cos\theta, the circle r=1r=1, and the rays θ=0\theta=0 and θ=π2\theta=\tfrac{\pi}{2}. Write, but do not evaluate, a definite integral whose value equals the area of this region.

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