MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability
Problem
Let y=(sinx)cosx for x∈(0,2π). The value of dxdy at x=4π is
(a) (sin4π)cos4π[42ln2+42]
(b) (sin4π)cos4π[42ln2+21]
(c) (sin4π)cos4π[−42ln2+21]
(d) (sin4π)cos4π[42ln2+1]