Let for . The value of at…

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

Let y=(sin⁡x)cos⁡xy=(\sin x)^{\cos x} for x∈(0,π2)x\in\left(0,\dfrac{\pi}{2}\right). The value of dydx\dfrac{dy}{dx} at x=π4x=\dfrac{\pi}{4} is (a) (sin⁡π4)cos⁡π4[24 ln⁡2+24](\sin\dfrac{\pi}{4})^{\cos\dfrac{\pi}{4}}\left[\dfrac{\sqrt{2}}{4}\,\ln 2+\dfrac{\sqrt{2}}{4}\right] (b) (sin⁡π4)cos⁡π4[24 ln⁡2+12](\sin\dfrac{\pi}{4})^{\cos\dfrac{\pi}{4}}\left[\dfrac{\sqrt{2}}{4}\,\ln 2+\dfrac{1}{\sqrt{2}}\right] (c) (sin⁡π4)cos⁡π4[−24 ln⁡2+12](\sin\dfrac{\pi}{4})^{\cos\dfrac{\pi}{4}}\left[-\dfrac{\sqrt{2}}{4}\,\ln 2+\dfrac{1}{\sqrt{2}}\right] (d) (sin⁡π4)cos⁡π4[24 ln⁡2+1](\sin\dfrac{\pi}{4})^{\cos\dfrac{\pi}{4}}\left[\dfrac{\sqrt{2}}{4}\,\ln 2+1\right]

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