Let be the vertex and be the latus rectum of the parabola

MATHEMATICS · Multi correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

Let VV be the vertex and LL be the latus rectum of the parabola x2=2y+4x−4x^2=2y+4x-4. Then the equation of the parabola whose vertex is at VV, whose latus rectum is L/2L/2, and whose axis is perpendicular to the axis of the given parabola is (1) y2=x−2y^2=x-2 (2) y2=x−4y^2=x-4 (3) y2=2−xy^2=2-x (4) y2=4−xy^2=4-x

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