Consider the infinite series (-1 )^ n+1 1 n = 1 - 1 2 + 1 3 - 1 4 + 1 5 - Answer the…

MATHEMATICS · Multi-part · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

Consider the infinite series (−1)n+11n=1−12+13−14+15−⋯\bigl(-1\bigr)^{n+1}\frac{1}{n} = 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \frac{1}{5} - \cdots Answer the following about this series and related concepts. (1) Part 1: (a) State a precise mathematical definition of absolute convergence for an infinite series ∑n=1∞an\sum_{n=1}^{\infty} a_n. Your definition must use the series built from ∣an∣|a_n|. (2) Part 2: (b) Determine whether the given series is absolutely convergent. Provide complete reasoning that references the definition you stated in part (a). (3) Part 3: (c) A series that converges but fails to satisfy the criterion in part (a) is said to converge conditionally. Explain in clear, logically ordered sentences why the given series is classified as conditionally convergent.

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