The equation to the common tangents to the two hyperbolas and are

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

The equation to the common tangents to the two hyperbolas x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 and y2a2−x2b2=1\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 are (a) y=±x±b2−a2y = \pm x \pm \sqrt{b^2 - a^2} (b) y=±x±(a2−b2)y = \pm x \pm (a^2 - b^2) (c) y=±x±a2−b2y = \pm x \pm \sqrt{a^2 - b^2} (d) y=±x±a2+b2y = \pm x \pm \sqrt{a^2 + b^2}

Related theory

Browse the problem library