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Eliminating time between the equations and for motion with constant acceleration…
PHYSICS · Single correct · CBSE · Physics · Motion · Motion
Problem
Eliminating time
t
t
t
between the equations
v
=
u
+
a
t
v = u + at
v
=
u
+
a
t
and
s
=
u
t
+
1
2
a
t
2
s = ut + \tfrac{1}{2} a t^{2}
s
=
u
t
+
2
1
a
t
2
for motion with constant acceleration yields which of the following relations? (a)
v
2
=
u
2
+
a
s
v^{2} = u^{2} + as
v
2
=
u
2
+
a
s
(b)
v
=
u
2
+
2
a
s
v = \sqrt{u^{2}+2as}
v
=
u
2
+
2
a
s
(c)
v
2
=
u
2
+
2
a
s
v^{2} = u^{2} + 2as
v
2
=
u
2
+
2
a
s
(d)
s
=
v
2
−
u
2
a
s = \dfrac{v^{2}-u^{2}}{a}
s
=
a
v
2
−
u
2
Related theory
Kinematic Equations for Uniform Acceleration
Kinematic Equations
Motion in a straight line
Acceleration
Equations of motion and numerical applications
Motion
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