If , and then and are…

MATHEMATICS · Single correct · CBSE · Mathematics · Arithmetic Progressions · Arithmetic Progressions

Problem

If H≡x2a2−y2b2−1=0H \equiv \frac{x^2}{a^2} - \frac{y^2}{b^2} - 1 = 0 , C≡x2a2−y2b2+1=0C \equiv \frac{x^2}{a^2} - \frac{y^2}{b^2} + 1 = 0 and A≡x2a2−y2b2=0A \equiv \frac{x^2}{a^2} - \frac{y^2}{b^2} = 0 then H,AH, A and CC are in (1) AP (2) GP (3) HP (4) AGP

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