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And side corresponds to
MATHEMATICS · Single correct · CBSE · Mathematics · Triangles · Triangles
Problem
Δ
A
B
C
∼
Δ
D
E
F
\Delta ABC \sim \Delta DEF
Δ
A
B
C
∼
Δ
D
E
F
and side
A
C
AC
A
C
corresponds to
D
F
DF
D
F
. If
A
C
=
6
3
cm
AC = 6\sqrt{3}\,\text{cm}
A
C
=
6
3
cm
,
D
F
=
9
3
cm
DF = 9\sqrt{3}\,\text{cm}
D
F
=
9
3
cm
, and the altitude from
C
C
C
to
A
B
AB
A
B
in
Δ
A
B
C
\Delta ABC
Δ
A
B
C
is
4
cm
4\,\text{cm}
4
cm
, find the corresponding altitude from
F
F
F
to
D
E
DE
D
E
in
Δ
D
E
F
\Delta DEF
Δ
D
E
F
. (a)
9
cm
9\,\text{cm}
9
cm
(b)
6
cm
6\,\text{cm}
6
cm
(c)
8
3
cm
\dfrac{8}{3}\,\text{cm}
3
8
cm
(d)
4
cm
4\,\text{cm}
4
cm
Related theory
Areas of Similar Triangles
Similarity
Similarity of Triangles
Triangle similarity conditions
Triangles
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