At 8:00 AM a truck departs on a straight freeway and travels east at a constant speed of

PHYSICS · Multi-part · CBSE · Physics · Motion in a Straight Line · Motion in a Straight Line

Problem

At 8:00 AM a truck departs x=0x=0 on a straight freeway and travels east at a constant speed of 20 m/s20\,\text{m/s}. Five minutes later (300 s300\,\text{s}) a sports car leaves the same point, starting from rest and accelerating eastward at a constant rate of 2 m/s22\,\text{m/s}^2. The motions continue for several minutes. Let tt be the number of seconds after 8:00 AM. (1) Part 1: For t≥0t\ge 0 write an expression for the truck’s position xT(t)x_T(t) in meters. For t≥300t\ge 300 write an expression for the car’s position xC(t)x_C(t). Clearly indicate the domain of each expression. (2) Part 2: Determine the time (in seconds after 8:00 AM) at which the car first reaches the truck. Give your answer to the nearest tenth of a second and justify that any other solution is extraneous for this context. (3) Part 3: Compute the distance east of the origin at which the meeting in part (b) occurs. (4) Part 4: Find the speed of the car at the instant it reaches the truck. Comment on how this speed compares to the truck’s speed.

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