For the relation

MATHEMATICS · Single correct · A Level · Mathematics · Differentiation · Differentiation

Problem

For the relation xtan⁡y+y=0x\tan y+y=0, find dydx\dfrac{dy}{dx} in terms of xx and yy. (a) tan⁡yxsec⁡2y+1\displaystyle\frac{\tan y}{x\sec^{2}y+1} (b) −tan⁡yxsec⁡2y−1\displaystyle\frac{-\tan y}{x\sec^{2}y-1} (c) −tan⁡yxsec⁡2y+1\displaystyle\frac{-\tan y}{x\sec^{2}y+1} (d) −tan⁡yx+1\displaystyle\frac{-\tan y}{x+1}

Related theory

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