Given: , and , , calculate the equilibrium constant for…

CHEMISTRY · Single correct · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

Given: Hg22++2e−⟶2Hg\text{Hg}_2^{2+} + 2\text{e}^- \longrightarrow 2\text{Hg}, E0=0.789 VE^0 = 0.789\text{ V} and Hg2++2e−⟶Hg\text{Hg}^{2+} + 2\text{e}^- \longrightarrow \text{Hg}, E0=0.854 VE^0 = 0.854\text{ V}, calculate the equilibrium constant for Hg22+⇌Hg+Hg2+\text{Hg}_2^{2+} \rightleftharpoons \text{Hg} + \text{Hg}^{2+}. (a) 3.13×10−33.13 \times 10^{-3} (b) 3.13×10−43.13 \times 10^{-4} (c) 6.26×10−36.26 \times 10^{-3} (d) 6.26×10−46.26 \times 10^{-4}

Related theory

Browse the problem library