For a polar curve whose equation produces negative -values on part of the interval

MATHEMATICS · Single correct · AP · Calculus BC · Parametric, Polar, and Vector-Valued Functions · Parametric, Polar, and Vector-Valued Functions

Problem

For a polar curve whose equation produces negative rr-values on part of the interval α≤θ≤β\alpha \le \theta \le \beta, a student wants to compute the exact area of the region traced once as θ\theta increases from α\alpha to β\beta. Which procedure best guarantees that the calculated area is correct? (a) Integrate 12r2\tfrac12 r^{2} only over the portion of the interval where r>0r>0 and then double the result, since the part where r<0r<0 is a reflected copy. (b) Integrate 12r2\tfrac12 r^{2} over the entire interval α≤θ≤β\alpha \le \theta \le \beta; squaring rr removes the sign, so the integral yields the desired area. (c) Integrate rr over α≤θ≤β\alpha \le \theta \le \beta and square the value you obtain to make the area positive. (d) Replace rr with ∣r∣|r| in the integrand and divide the final answer by 22 to correct for the absolute value.

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