At the elementary decomposition of dinitrogen tetraoxide follows with rate laws…

CHEMISTRY · Multi-part · A Level · Chemistry · Chemical equilibria (Le Chatelier’s principle and Kc) · Chemical equilibria (Le Chatelier’s principle and Kc)

Problem

At 350 K350\,\text{K} the elementary decomposition of dinitrogen tetraoxide follows N2O4(g)⇋2 NO2(g)N_{2}O_{4}(g) \leftrightharpoons 2\,NO_{2}(g) with rate laws Forward rate = kf[N2O4]k_f[N_{2}O_{4}] and Reverse rate = kr[NO2]2k_r[NO_{2}]^{2}. The rate constants at 350 K350\,\text{K} are kf=0.082 s−1k_f = 0.082\,\text{s}^{-1} and kr=1.9×10−2 kPa−1⋅s−1k_r = 1.9 \times 10^{-2}\,\text{kPa}^{-1}\cdot\text{s}^{-1} when partial pressures are expressed in kPa. A sealed 1.00 L1.00\,\text{L} flask initially contains pure N2O4N_{2}O_{4} at 15 kPa15\,\text{kPa} and no NO2NO_{2}. (a) Write expressions for the forward and reverse rates as functions of time in terms of the changing partial pressures of N2O4N_{2}O_{4} and NO2NO_{2}. (b) Assuming that x kPax\,\text{kPa} of N2O4N_{2}O_{4} has decomposed at time tt, express the forward and reverse rates in terms of xx. (c) Determine the value of xx (in kPa) at which the forward and reverse rates become equal. Show algebraic work and report xx to two significant figures. (d) Calculate the partial pressure of each species at the moment equilibrium is first established. Does the system necessarily remain at these pressures indefinitely? Explain.

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