An ice sphere melts so that its radius (in centimeters) decreases at the constant rate

MATHEMATICS · Multi-part · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

An ice sphere melts so that its radius r(t)r(t) (in centimeters) decreases at the constant rate drdt=−0.05 cm/min\dfrac{dr}{dt}=-0.05\,\text{cm/min}. The surface-area–to–volume ratio is S(t)=4πr(t)243πr(t)3=3r(t)S(t)=\dfrac{4\pi r(t)^{2}}{\tfrac{4}{3}\pi r(t)^{3}}=\dfrac{3}{r(t)}. (a) Derive a formula for dSdt\dfrac{dS}{dt} in terms of r(t)r(t) and drdt\dfrac{dr}{dt}. (b) The melting begins with radius r(0)=5 cmr(0)=5\,\text{cm}. Determine the time, in minutes, at which dSdt=0.03 cm−2/min\dfrac{dS}{dt}=0.03\,\text{cm}^{-2}\text{/min}.

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