A pendulum consists of a bob on a light rigid rod of length

PHYSICS · Subjective · Fermi University Physics · Mechanics & Dynamical Systems · Oscillations and normal modes · Lagrangian mechanics

Action and Symmetry, Ch The action, the first variation and the boundary term

Problem

A pendulum consists of a bob on a light rigid rod of length ℓp=1.0 m\ell_{\rm p} = 1.0\,\mathrm{m}, free to swing in a vertical plane under gravity (g=9.8 m s−2g = 9.8\,\mathrm{m\,s^{-2}}), released from rest at a small angle θ0\theta_0 from the vertical. For small θ0\theta_0 the restoring torque is proportional to θ\theta to good approximation, so the swing is simple harmonic with angular frequency ω=g/ℓp\omega = \sqrt{g/\ell_{\rm p}}. Up to a constant, its small-angle Lagrangian L=12mℓp2θ˙2−12mgℓpθ2L = \tfrac12 m\ell_{\rm p}^2\dot\theta^2 - \tfrac12 mg\ell_{\rm p}\theta^2 has the same quadratic form as that of the mass-spring oscillator, with mℓp2m\ell_{\rm p}^2 in place of the mass, whose action was examined for a sinusoidal trial variation elsewhere. Estimate the time after release of the true swinging path's first conjugate point, using the oscillator result that this occurs at half a period, and say what that time means for whether the path minimises the action.

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