A bead slides on a circular wire of radius that is being lifted vertically at a…

PHYSICS · Multi-part · Fermi University Physics · Mechanics & Dynamical Systems · Lagrangian mechanics · Lagrangian mechanics

Action and Symmetry, Ch Constraints, generalised coordinates and Lagrange's equations twice over

Problem

A bead slides on a circular wire of radius a=0.25 ma=0.25\,\mathrm{m} that is being lifted vertically at a constant speed V=0.40 m s−1V=0.40\,\mathrm{m\,s^{-1}}. Using arc length ss measured along the wire from its lowest point, and writing t^\hat{\mathbf t} for the wire's unit tangent, someone reasons as follows: "The wire's own motion has to be included, otherwise the calculation misses the work the lift does. In a short time δt\delta t the wire rises by V δtV\,\delta t, so I will take the virtual displacement to be δr=t^ δs+V δt z^.\delta\mathbf r = \hat{\mathbf t}\,\delta s + V\,\delta t\,\hat{\mathbf z}. Since the push N\mathbf N from the wire is perpendicular to t^\hat{\mathbf t} but not to z^\hat{\mathbf z}, I conclude the virtual work of the push, N⋅δr\mathbf N\cdot\delta\mathbf r, is not zero." ((a)) Find the error in this reasoning and state which definition it conflicts with. ((b)) Give the correct virtual displacement and the correct value of N⋅δr\mathbf N\cdot\delta\mathbf r. State, separately, whether the real work done by the push over an actual time δt\delta t is zero.

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