The Sun has mass and Mercury orbits at a mean distance from the Sun's centre

PHYSICS · Multi-part · Fermi University Physics · Mechanics & Dynamical Systems · Rotation, rigid bodies and accelerated frames · Gravitation and central-force motion

Action and Symmetry, Ch Non-inertial frames from one Lagrangian

Problem

The Sun has mass M⊙=1.989×1030 kgM_\odot = 1.989\times10^{30}\ \mathrm{kg} and Mercury orbits at a mean distance d=5.79×1010 md = 5.79\times10^{10}\ \mathrm{m} from the Sun's centre. Treat the Sun as a point mass. Take Cartesian axes centred on Mercury's centre such that the unit vector towards the Sun is n=(cos⁡45∘,sin⁡45∘,0)\mathbf n = (\cos45^\circ,\sin45^\circ,0), i.e. tilted at 45∘45^\circ to the xx-axis in the xyxy-plane. ((a)) Find all the (generally nonzero) components TxxT_{xx}, TyyT_{yy}, TzzT_{zz}, TxyT_{xy} of the Sun's tidal tensor at Mercury's centre. ((b)) Verify that the trace vanishes.

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