(a) A rigid body has principal moments of inertia , , about its centre of mass, with…

PHYSICS · Subjective · Fermi University Physics · Mechanics & Dynamical Systems · Rotation, rigid bodies and accelerated frames · Oscillations and normal modes

Action and Symmetry, Ch Small oscillations: stability, degeneracy, symmetry and spectra

Problem

(a) A rigid body has principal moments of inertia I1=2.0 kg m2I_1 = 2.0\,\mathrm{kg\,m^2}, I2=3.0 kg m2I_2 = 3.0\,\mathrm{kg\,m^2}, I3=5.0 kg m2I_3 = 5.0\,\mathrm{kg\,m^2} about its centre of mass, with I1<I2<I3I_1 < I_2 < I_3. No external torque acts. It is set spinning freely about the intermediate axis (axis 2) at Ω=4.0 rad s−1\Omega = 4.0\,\mathrm{rad\,s^{-1}}. Linearise Euler's torque-free equations for a small perturbation (ω1,ω3)(\omega_1,\omega_3) away from this spin, write the pair as an eigenvalue problem for a rate λ\lambda such that the perturbation behaves as exp⁡(λt)\exp(\lambda t), find λ\lambda, and state whether the spin is stable. (b) In the rotating restricted three-body problem the effective potential's Hessian at the Lagrange point L4L_4 has two negative eigenvalues (a maximum) for every mass ratio μ2=m2/(m1+m2)\mu_2 = m_2/(m_1+m_2), yet L4L_4 is observed to hold test masses (the Trojan asteroids) when μ2\mu_2 is small enough. The stability condition derived for L4L_4 in Chapter 10 places the stability boundary at μ2,crit=0.0385\mu_{2,\rm crit} = 0.0385, and the Sun-Jupiter system has μ2=9.5×10−4\mu_2 = 9.5\times10^{-4}. Decide whether L4L_4 is stable there, and explain why a maximum of the effective potential does not by itself decide the answer for this system. (c) A free rigid molecule that is not linear and has no continuous internal symmetry has 3N3N coordinates and, by the zero-mode count for a free system, 66 zero-frequency normal modes: 33 translational and 33 rotational. State which conserved quantity, identified by Noether's theorem, is associated with the three translational zero modes, and which with the three rotational zero modes.

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