A particle of mass kg moves in a plane under the isotropic potential with

PHYSICS · Multi-part · Fermi University Physics · Mechanics & Dynamical Systems · Gravitation and central-force motion · Hamiltonian mechanics and canonical structure

Action and Symmetry, Ch Hamilton-Jacobi theory and action-angle variables

Problem

A particle of mass μ=0.50\mu = 0.50 kg moves in a plane under the isotropic potential V(r)=12κr2V(r) = \tfrac12\kappa r^2 with κ=8.0 N m−1\kappa = 8.0\,\mathrm{N\,m^{-1}}. Its energy is E=2.0E = 2.0 J and its angular momentum about the centre is ℓ=0.40 kg m2 s−1\ell = 0.40\,\mathrm{kg\,m^2\,s^{-1}}. ((a)) Write the Hamiltonian in plane polar coordinates (r,φ)(r,\varphi), write S=W(r,φ)−EtS = W(r,\varphi) - Et, and separate the Hamilton-Jacobi equation, identifying the constants EE and ℓ\ell and writing the radial equation for pr(r)p_r(r). ((b)) For this potential the radial loop integral is a standard result, Ir=E2ω−ℓ2I_r = \dfrac{E}{2\omega} - \dfrac{\ell}{2} with ω=κ/μ\omega = \sqrt{\kappa/\mu}. Find the energy EcircE_{\rm circ} of the circular orbit that has this same ℓ\ell (the orbit with Ir=0I_r = 0), and compare it with the given EE. ((c)) Write HH in terms of IrI_r and Iφ=ℓI_\varphi = \ell, and use νk=∂H/∂Ik\nu_k = \partial H/\partial I_k to find the radial frequency νr\nu_r and the angular frequency νφ\nu_\varphi. ((d)) Hence find the angle swept from one closest approach to the next, and state whether the orbit is closed.

Browse the problem library