Someone argues: "the action variable has units of joule-seconds

PHYSICS · Multi-part · Fermi University Physics · Mechanics & Dynamical Systems · Hamiltonian mechanics and canonical structure · Hamiltonian mechanics and canonical structure

Action and Symmetry, Ch Hamilton-Jacobi theory and action-angle variables

Problem

Someone argues: "the action variable II has units of joule-seconds, exactly the units of the action S=∫L dtS=\int L\,\mathrm{d}t of Chapter 1. So 2πI2\pi I must just be that action, evaluated over one period: 2πI=∫0τL dt2\pi I = \displaystyle\int_0^\tau L\,\mathrm{d}t." Test this for a ball of mass m=0.10m = 0.10 kg bouncing elastically on a floor from a height h=2.0h = 2.0 m, with g=9.8 m s−2g = 9.8\,\mathrm{m\,s^{-2}}, potential energy V=mgxV = mgx and xx its height above the floor. ((a)) Compute 2πI2\pi I from the area of the loop the motion traces in the (x,p)(x,p) plane. ((b)) Compute ∫0τL dt\displaystyle\int_0^\tau L\,\mathrm{d}t directly from the motion, over one full bounce period τ\tau. ((c)) Say where the argument goes wrong, and check your two numbers against ∮p dx=∫0τ(L+H) dt\oint p\,\mathrm{d}x = \displaystyle\int_0^\tau(L+H)\,\mathrm{d}t.

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