A shear-thinning varnish with no yield stress obeys the power law

PHYSICS · Multi-part · Fermi University Physics · Fluids & Continuum Physics · Solid continuum mechanics and complex fluids · Solid continuum mechanics and complex fluids

Bending, Ringing, Breaking and Flowing, Ch Non-Newtonian and viscoelastic fluids

Problem

A shear-thinning varnish with no yield stress obeys the power law τ=Kγ˙n\tau = K\dot\gamma^n, with K=4.0 Pa s0.5K = 4.0\,\mathrm{Pa\,s^{0.5}}, n=0.50n = 0.50 and density ρ=1200 kg m−3\rho = 1200\,\mathrm{kg\,m^{-3}}. A coat of uniform thickness hh drains steadily down a tall vertical wall. Measure yy outward from the wall, which is at y=0y = 0; the free surface at y=hy = h carries no shear stress. Take g=9.8 m s−2g = 9.8\,\mathrm{m\,s^{-2}}. ((a)) By balancing forces on the layer of varnish between a plane at distance yy and the free surface, find the shear stress τ(y)\tau(y). ((b)) Derive the downward velocity u(y)u(y), with u(0)=0u(0) = 0, and the flow rate per unit width of wall q=∫0hu dyq = \int_0^h u\,\mathrm{d}y. Show that n=1n = 1, K=ηK = \eta gives the Newtonian film result q=ρgh3/3ηq = \rho g h^3/3\eta. ((c)) For h=0.50 mmh = 0.50\,\mathrm{mm}, evaluate the surface speed u(h)u(h) and qq. By what factor does qq grow if the coat is laid on twice as thick, and how does that compare with a Newtonian varnish?

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