A capacitor discharges through a resistor according to

PHYSICS · Subjective · Fermi University Physics · Scientific Practice & Experimental Methods · Mathematical Methods for Physics · Uncertainty in measurement

Computational Physics, Ch Numbers a machine can hold, and the two errors that follow

Problem

A capacitor discharges through a resistor according to V(t)=V0e−t/τV(t) = V_0 e^{-t/\tau}, where V0=9.00 VV_0 = 9.00\,\mathrm{V} is the initial voltage and τ=2.50 ms\tau = 2.50\,\mathrm{ms} is the (exactly known) time constant. The elapsed time is measured as t=7.50 mst = 7.50\,\mathrm{ms} with a relative uncertainty of 0.30%0.30\%. (a) Compute the condition number κ=∣tf′(t)/f(t)∣\kappa = |t f'(t)/f(t)| of VV as a function of tt, evaluated at t=7.50 mst = 7.50\,\mathrm{ms}. (b) Use κ\kappa to bound the relative uncertainty in the computed voltage V(t)V(t), and give V(t)V(t) with its absolute uncertainty. (c) Suppose instead tt had no measurement uncertainty at all and were simply stored as an IEEE 754 binary64 value. Give the resulting relative error in tt from storage alone, and say whether it changes the answer to part (ii).

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