Parabolic cylindrical coordinates

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Vector calculus and field geometry · Vector calculus and field geometry

Conditions of Validity, Ch Gradient, divergence and curl without coordinates, and with any coordinates

Problem

Parabolic cylindrical coordinates (u,v,z)(u,v,z), with u≥0u \ge 0 and v∈Rv \in \mathbb{R}, are defined by x=12(u2−v2),y=uv,z=z.x = \tfrac{1}{2}(u^2-v^2), \qquad y = uv, \qquad z = z. Treat uu, vv, xx, yy, zz as dimensionless, purely mathematical coordinates for this problem. ((a)) Following the method used for the coordinate basis and metric (Chapter 3), compute eu\mathbf{e}_u, ev\mathbf{e}_v, ez\mathbf{e}_z, the metric coefficients gijg_{ij}, and g\sqrt g. ((b)) Independently, using the change-of-variables Jacobian (Chapter 2), compute J=∂(x,y,z)/∂(u,v,z)J = \partial(x,y,z)/\partial(u,v,z) directly from the given formulas for x,y,zx,y,z, and check that J=gJ = \sqrt g. ((c)) A vector field has physical components Fu^=AuF_{\hat u} = Au, Fv^=0F_{\hat v} = 0, Fz^=0F_{\hat z} = 0, where A=3.0A = 3.0 is a constant. Using the general divergence formula (1/g)∂i(gFi)(1/\sqrt g)\partial_i(\sqrt g F^i), find ∇⋅F\nabla\cdot\mathbf{F} as a function of uu and vv, and evaluate it at u=2.0u = 2.0, v=1.0v = 1.0.

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