A two-dimensional crystal lattice has basis vectors and

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Linear algebra and vector spaces · Linear algebra and vector spaces

Conditions of Validity, Ch Vector spaces, linear maps and the dual: the Riesz theorem

Problem

A two-dimensional crystal lattice has basis vectors e1=(1,0) nm\mathbf{e}_1=(1,0)\,\mathrm{nm} and e2=(1,3) nm\mathbf{e}_2=(1,3)\,\mathrm{nm}, non-orthogonal, with the ordinary Euclidean dot product. A uniform force field does work ω(v)=F⋅v\omega(\mathbf{v})=\mathbf{F}\cdot\mathbf{v} on a displacement v\mathbf{v} lying in the lattice plane. It is measured that the work done for a displacement equal to e1\mathbf{e}_1 is 2 eV2\,\mathrm{eV} and for a displacement equal to e2\mathbf{e}_2 is 5 eV5\,\mathrm{eV}. ((a)) Write down the metric gij=ei⋅ejg_{ij}=\mathbf{e}_i\cdot\mathbf{e}_j of the lattice basis and invert it. ((b)) Use ui=gijωju^i=g^{ij}\omega_j to find the components of F\mathbf{F} in the lattice basis, then convert to Cartesian (nm) components. ((c)) Check the result directly against the two given work values.

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